JEE (Advanced) · Chemistry, Class 12
Biomolecules: JEE Advanced PYQ, 2007–2026
Biomolecules (Chemistry, Class 12) has been asked 27 times in the 40 JEE (Advanced) papers from 2007–2026: about 0.7 questions a paper, 4% of all Chemistry questions. It is the 12th most-asked of 31 Chemistry chapters. The two 2026 papers had 2 from it. Last checked 28 October 2026.
Questions per year, both papers
Year by year.
| Year | Questions |
|---|---|
| 2007 | 1in 2 papers |
| 2008 | 1in 2 papers |
| 2009 | 1in 2 papers |
| 2010 | 2in 2 papers |
| 2011 | 2in 2 papers |
| 2012 | 2in 2 papers |
| 2013 | 1in 2 papers |
| 2014 | 1in 2 papers |
| 2015 | 1in 2 papers |
| 2016 | 2in 2 papers |
| 2017 | 0in 2 papers |
| 2018 | 1in 2 papers |
| 2019 | 1in 2 papers |
| 2020 | 2in 2 papers |
| 2021 | 1in 2 papers |
| 2022 | 1in 2 papers |
| 2023 | 1in 2 papers |
| 2024 | 2in 2 papers |
| 2025 | 2in 2 papers |
| 2026 | 2in 2 papers |
Each year has two papers, and the number of questions has fallen over time, so compare per paper and expect some drift.
Inside the chapter
Topics asked most.
- Carbohydrates17
- Proteins9
- Nucleic acids and vitamins1
Try it
10 Biomolecules questions to practise.
Our own questions, written in the JEE Advanced pattern and checked, each with an explanation. Pick an option to see the answer.
Q1 · Chemistry · Biomolecules
Most water-soluble vitamins are excreted in urine and are not stored in the body, whereas fat-soluble vitamins are stored in the liver and adipose tissue. Which of the following vitamins is water-soluble and yet stored in the liver?
Answer: (A)
Vitamins A, D, E and K are fat-soluble and are stored in the liver and adipose tissue. Vitamins of the B group and vitamin C are water-soluble and are excreted in urine, so they must be supplied regularly. Vitamin B₁₂ is the exception: it is water-soluble but is stored in the liver. The answer must meet both conditions, so vitamin A is out because it is fat-soluble, and vitamins C and B₆ are out because they are not stored.
Q2 · Chemistry · Biomolecules
Both D-glucose and D-fructose give a positive Tollens' test, but only D-glucose is oxidised by bromine water to gluconic acid. Which explanation accounts for this difference?
Answer: (A)
Tollens' reagent is alkaline (ammoniacal silver nitrate). In base, fructose undergoes keto–enol tautomerism through an enediol intermediate and is converted into glucose and mannose, both aldoses, which reduce Ag⁺ to Ag. Bromine water is a mild, non-basic oxidant that oxidises the –CHO group of aldoses to –COOH but does not oxidise a ketone, and it does not cause the isomerisation. So glucose is oxidised to gluconic acid and fructose is not. The other options wrongly give fructose an aldehyde group, invoke C–C cleavage by a mild oxidant, or explain the difference by ring structure, which is the same for both reagents.
Q3 · Chemistry · Biomolecules
D-Glucose is oxidised separately with (i) bromine water and (ii) concentrated nitric acid. How many –COOH groups does the main product of each reaction contain, in the order (i), (ii)?
Answer: (A)
Principle: the oxidation product of glucose depends on the strength of the oxidant. Bromine water is mild and oxidises only the aldehyde group (C1) to –COOH, giving gluconic acid, HOOC–(CHOH)4–CH2OH, with one –COOH. Concentrated HNO3 is a strong oxidant and oxidises both the –CHO at C1 and the primary –CH2OH at C6, giving saccharic acid, HOOC–(CHOH)4–COOH, with two –COOH groups. The answer is therefore 1 and 2.
Q4 · Chemistry · Biomolecules
Which of the following sets lists one hormone each from the steroid, polypeptide and amino-acid-derivative classes, in that order?
Answer: (A)
Hormones are grouped into three chemical classes. Steroids include testosterone, estradiol, progesterone and the adrenocortical hormones such as cortisol. Polypeptides include insulin, glucagon and oxytocin. Amino-acid derivatives include thyroxine, which is an iodinated tyrosine derivative, and adrenaline. For the order steroid, polypeptide, amino-acid derivative, only 'testosterone, glucagon, thyroxine' fits. The other sets either swap classes between positions or misclassify cortisol.
Q5 · Chemistry · Biomolecules
Thyroxine, the principal hormone of the thyroid gland, is best described as:
Answer: (B)
Hormones fall into three broad classes: steroids, polypeptides, and amino acid derivatives. Thyroxine belongs to the amino acid derivatives. It is formed from tyrosine by iodination of the aromatic ring, which explains why it needs iodine. It is neither a steroid nor a polypeptide, and tryptophan is not its precursor.
Q6 · Chemistry · Biomolecules
Three patients show the following deficiency symptoms: Patient 1 has convulsions, Patient 2 has pernicious anaemia, and Patient 3 has increased blood clotting time. Which option correctly names the vitamins deficient in Patients 1, 2 and 3 respectively, and correctly states how many of these three vitamins are fat-soluble?
Answer: (A)
Principle: each vitamin has a characteristic deficiency disorder, and solubility (fat or water) is a separate property from where the vitamin is stored. Application: convulsions point to vitamin B₆ (pyridoxine). Pernicious anaemia points to vitamin B₁₂ (cobalamin). Increased blood clotting time points to vitamin K. Vitamins A, D, E and K are fat-soluble. The B-complex vitamins (B₆, B₁₂) and vitamin C are water-soluble. So only K is fat-soluble, even though B₁₂ is stored in the liver.
Q7 · Chemistry · Biomolecules
A patient shows convulsions that are traced to a vitamin deficiency. Which option names the deficient vitamin and a dietary source that supplies it?
Answer: (A)
Each vitamin is linked to a specific deficiency disorder. Pyridoxine (B₆) deficiency causes convulsions, and it occurs in yeast, milk, egg yolk, cereals and gram. B₁₂ deficiency causes pernicious anaemia, B₁ deficiency causes beri-beri, and K deficiency lengthens blood clotting time. So only the first option pairs the symptom with the right vitamin.
Q8 · Chemistry · Biomolecules
A dilute solution of a globular protein is heated until it turns cloudy and a white coagulate separates, as when egg white is boiled. The protein is not treated with any acid, base or enzyme. Which of the following correctly describes the change?
Answer: (A)
Denaturation is the loss of the native three-dimensional structure of a protein by heat, pH change or similar agents. Heating supplies enough energy to break the weak non-covalent interactions (hydrogen bonds, ionic and hydrophobic interactions) that maintain the secondary and tertiary structures. The folded chain unfolds, exposes its hydrophobic groups, and the protein aggregates and coagulates. The covalent peptide bonds are much stronger and are not hydrolysed under these conditions, so the primary structure is retained. Hydrolysis to amino acids needs strong acid or base, or enzymes. Quaternary structure, if present, is lost along with the secondary and tertiary structures, not on its own.
Q9 · Chemistry · Biomolecules
Fructose is a ketohexose, yet it reduces Tollens' reagent. Which of the following best explains this?
Answer: (A)
Principle: Tollens' reagent oxidises aldehydes, not ketones. Application: fructose has a C2 ketone, but in the basic medium it equilibrates through an enediol with glucose and mannose, which have a free –CHO group in the open-chain form. These aldoses reduce Ag⁺ to silver, and removing them drives further isomerisation of fructose. So the reducing action comes from rearrangement, not from the ketone, which is why the correct option is the enediol rearrangement.
Q10 · Chemistry · Biomolecules
A synthetic double-stranded DNA fragment is 6 base pairs long. Assume each of its 12 nucleotides was built from a free nitrogenous base, 2-deoxyribose and phosphoric acid, using only condensation steps. These are: base + sugar → nucleoside, nucleoside + phosphoric acid → nucleotide (one phosphate ester each), and nucleotide + nucleotide → phosphodiester link within a strand. How many water molecules are released in building the fragment? (Hydrogen bonds between the strands release no water.)
Answer: (C)
Count each condensation step separately. (1) Each base–sugar bond (N-glycosidic link) releases one H₂O, so 12 nucleosides give 12 H₂O. (2) Esterifying each nucleoside with one phosphoric acid releases one H₂O, so 12 nucleotides give 12 H₂O. (3) A strand of n nucleotides has n − 1 phosphodiester links. The duplex has two strands of 6, so 2 × 5 = 10 links and 10 H₂O. The total is 12 + 12 + 10 = 34. The hydrogen bonds between base pairs are non-covalent and release no water.
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All 27 real JEE Advanced questions from Biomolecules.
The questions from the actual papers, with the official answer and an explanation for each — chapter by chapter, or as full timed papers.
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About Biomolecules in JEE Advanced.
How many questions come from Biomolecules in JEE Advanced?
Biomolecules (Chemistry, Class 12) has been asked 27 times in the 40 JEE (Advanced) papers from 2007–2026: about 0.7 questions a paper, 4% of all Chemistry questions. It is the 12th most-asked of 31 Chemistry chapters. The two 2026 papers had 2 from it.
Which topics of Biomolecules are asked most in JEE Advanced?
Carbohydrates (17), Proteins (9), Nucleic acids and vitamins (1), counted over the papers from 2007–2026.
Is Biomolecules important for JEE Advanced 2027?
It is in the syllabus in force, so it can be asked. By past papers it ranks 12 of 31 in Chemistry; use that to decide how much time it gets, not whether to study it.
Where can I solve Biomolecules JEE Advanced previous year questions?
On Nikaalle, free: sign up and practise every past JEE Advanced question from Biomolecules with an explanation for each, or sit the full papers timed. The ten questions on this page are our own, written in the same pattern.
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